HomeCompare → Bloomington vs San Angelo

Bloomington, MN vs San Angelo, TX

Bloomington, MN

65
Grade: C
Violent Rate311.8/100k
Property Rate3464.3/100k
Population86,598
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San Angelo, TX

71
Grade: B
Violent Rate218.2/100k
Property Rate2486.0/100k
Population98,996
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🏆 San Angelo is Safer

by 6 points

Frequently Asked Questions

Is Bloomington, MN or San Angelo, TX safer?

San Angelo is safer with a higher safety score by 6 points. Bloomington, MN has a safety score of 65/100 while San Angelo, TX has 71/100, based on FBI Uniform Crime Report data.

What is the violent crime rate in Bloomington, MN vs San Angelo, TX?

Bloomington, MN has a violent crime rate of 311.8 per 100,000 residents, while San Angelo, TX has 218.2 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

What is the property crime rate in Bloomington, MN vs San Angelo, TX?

Bloomington, MN has a property crime rate of 3464.3 per 100,000, compared to 2486.0 per 100,000 in San Angelo, TX. Property crimes include burglary, theft, and motor vehicle theft.

How are CrimeSafe safety scores calculated?

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Should I move to Bloomington, MN or San Angelo, TX?

Based on crime data alone, San Angelo is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.