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Bolingbrook, IL vs Iowa City, IA

Bolingbrook, IL

78
Grade: B
Violent Rate182.0/100k
Property Rate779.2/100k
Population74,177
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Iowa City, IA

69
Grade: C
Violent Rate321.3/100k
Property Rate1673.8/100k
Population75,934
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🏆 Bolingbrook is Safer

by 9 points

Frequently Asked Questions

Is Bolingbrook, IL or Iowa City, IA safer?

Bolingbrook is safer with a higher safety score by 9 points. Bolingbrook, IL has a safety score of 78/100 while Iowa City, IA has 69/100, based on FBI Uniform Crime Report data.

What is the violent crime rate in Bolingbrook, IL vs Iowa City, IA?

Bolingbrook, IL has a violent crime rate of 182.0 per 100,000 residents, while Iowa City, IA has 321.3 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

What is the property crime rate in Bolingbrook, IL vs Iowa City, IA?

Bolingbrook, IL has a property crime rate of 779.2 per 100,000, compared to 1673.8 per 100,000 in Iowa City, IA. Property crimes include burglary, theft, and motor vehicle theft.

How are CrimeSafe safety scores calculated?

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Should I move to Bolingbrook, IL or Iowa City, IA?

Based on crime data alone, Bolingbrook is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.