HomeCompare → Boynton Beach vs Cedar Rapids

Boynton Beach, FL vs Cedar Rapids, IA

Boynton Beach, FL

65
Grade: C
Violent Rate417.3/100k
Property Rate2283.0/100k
Population81,473
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Cedar Rapids, IA

68
Grade: C
Violent Rate261.5/100k
Property Rate2689.1/100k
Population135,363
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🏆 Cedar Rapids is Safer

by 3 points

Frequently Asked Questions

Is Boynton Beach, FL or Cedar Rapids, IA safer?

Cedar Rapids is safer with a higher safety score by 3 points. Boynton Beach, FL has a safety score of 65/100 while Cedar Rapids, IA has 68/100, based on FBI Uniform Crime Report data.

What is the violent crime rate in Boynton Beach, FL vs Cedar Rapids, IA?

Boynton Beach, FL has a violent crime rate of 417.3 per 100,000 residents, while Cedar Rapids, IA has 261.5 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

What is the property crime rate in Boynton Beach, FL vs Cedar Rapids, IA?

Boynton Beach, FL has a property crime rate of 2283.0 per 100,000, compared to 2689.1 per 100,000 in Cedar Rapids, IA. Property crimes include burglary, theft, and motor vehicle theft.

How are CrimeSafe safety scores calculated?

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Should I move to Boynton Beach, FL or Cedar Rapids, IA?

Based on crime data alone, Cedar Rapids is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.