Boynton Beach, FL vs Leander, TX

Leander is safer with a higher safety score by 21 points. Boynton Beach, FL has a safety score of 65/100 while Leander, TX has 86/100, based on FBI Uniform Crime Report data.

Boynton Beach, FL has a violent crime rate of 417.3 per 100,000 residents, while Leander, TX has 69.5 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

Boynton Beach, FL has a property crime rate of 2283.0 per 100,000, compared to 988.1 per 100,000 in Leander, TX. Property crimes include burglary, theft, and motor vehicle theft.

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Based on crime data alone, Leander is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.