Boynton Beach, FL vs Noblesville, IN

Noblesville is safer with a higher safety score by 23 points. Boynton Beach, FL has a safety score of 65/100 while Noblesville, IN has 88/100, based on FBI Uniform Crime Report data.

Boynton Beach, FL has a violent crime rate of 417.3 per 100,000 residents, while Noblesville, IN has 83.8 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

Boynton Beach, FL has a property crime rate of 2283.0 per 100,000, compared to 538.4 per 100,000 in Noblesville, IN. Property crimes include burglary, theft, and motor vehicle theft.

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Based on crime data alone, Noblesville is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.