Boynton Beach, FL vs Springfield, IL

Boynton Beach is safer with a higher safety score by 12 points. Boynton Beach, FL has a safety score of 65/100 while Springfield, IL has 53/100, based on FBI Uniform Crime Report data.

Boynton Beach, FL has a violent crime rate of 417.3 per 100,000 residents, while Springfield, IL has 901.2 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

Boynton Beach, FL has a property crime rate of 2283.0 per 100,000, compared to 4911.4 per 100,000 in Springfield, IL. Property crimes include burglary, theft, and motor vehicle theft.

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Based on crime data alone, Boynton Beach is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.