HomeCompare → Dearborn vs Scottsdale

Dearborn, MI vs Scottsdale, AZ

Dearborn, MI

69
Grade: C
Violent Rate292.6/100k
Property Rate1999.6/100k
Population104,571
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Scottsdale, AZ

75
Grade: B
Violent Rate152.5/100k
Property Rate1875.3/100k
Population245,237
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🏆 Scottsdale is Safer

by 6 points

Frequently Asked Questions

Is Dearborn, MI or Scottsdale, AZ safer?

Scottsdale is safer with a higher safety score by 6 points. Dearborn, MI has a safety score of 69/100 while Scottsdale, AZ has 75/100, based on FBI Uniform Crime Report data.

What is the violent crime rate in Dearborn, MI vs Scottsdale, AZ?

Dearborn, MI has a violent crime rate of 292.6 per 100,000 residents, while Scottsdale, AZ has 152.5 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

What is the property crime rate in Dearborn, MI vs Scottsdale, AZ?

Dearborn, MI has a property crime rate of 1999.6 per 100,000, compared to 1875.3 per 100,000 in Scottsdale, AZ. Property crimes include burglary, theft, and motor vehicle theft.

How are CrimeSafe safety scores calculated?

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Should I move to Dearborn, MI or Scottsdale, AZ?

Based on crime data alone, Scottsdale is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.