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Jonesboro, AR vs San Marcos, CA

Jonesboro, AR

58
Grade: D
Violent Rate719.9/100k
Property Rate3044.7/100k
Population81,256
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San Marcos, CA

77
Grade: B
Violent Rate222.4/100k
Property Rate659.8/100k
Population93,974
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🏆 San Marcos is Safer

by 19 points

Frequently Asked Questions

Is Jonesboro, AR or San Marcos, CA safer?

San Marcos is safer with a higher safety score by 19 points. Jonesboro, AR has a safety score of 58/100 while San Marcos, CA has 77/100, based on FBI Uniform Crime Report data.

What is the violent crime rate in Jonesboro, AR vs San Marcos, CA?

Jonesboro, AR has a violent crime rate of 719.9 per 100,000 residents, while San Marcos, CA has 222.4 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

What is the property crime rate in Jonesboro, AR vs San Marcos, CA?

Jonesboro, AR has a property crime rate of 3044.7 per 100,000, compared to 659.8 per 100,000 in San Marcos, CA. Property crimes include burglary, theft, and motor vehicle theft.

How are CrimeSafe safety scores calculated?

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Should I move to Jonesboro, AR or San Marcos, CA?

Based on crime data alone, San Marcos is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.