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Lakeville, MN vs San Leandro, CA

Lakeville, MN

88
Grade: A
Violent Rate76.5/100k
Property Rate571.2/100k
Population78,436
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San Leandro, CA

59
Grade: D
Violent Rate548.7/100k
Property Rate3922.8/100k
Population84,200
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🏆 Lakeville is Safer

by 29 points

Frequently Asked Questions

Is Lakeville, MN or San Leandro, CA safer?

Lakeville is safer with a higher safety score by 29 points. Lakeville, MN has a safety score of 88/100 while San Leandro, CA has 59/100, based on FBI Uniform Crime Report data.

What is the violent crime rate in Lakeville, MN vs San Leandro, CA?

Lakeville, MN has a violent crime rate of 76.5 per 100,000 residents, while San Leandro, CA has 548.7 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

What is the property crime rate in Lakeville, MN vs San Leandro, CA?

Lakeville, MN has a property crime rate of 571.2 per 100,000, compared to 3922.8 per 100,000 in San Leandro, CA. Property crimes include burglary, theft, and motor vehicle theft.

How are CrimeSafe safety scores calculated?

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Should I move to Lakeville, MN or San Leandro, CA?

Based on crime data alone, Lakeville is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.