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San Angelo, TX vs Sioux City, IA

San Angelo, TX

71
Grade: B
Violent Rate218.2/100k
Property Rate2486.0/100k
Population98,996
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Sioux City, IA

60
Grade: C
Violent Rate555.4/100k
Property Rate3324.0/100k
Population85,711
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🏆 San Angelo is Safer

by 11 points

Frequently Asked Questions

Is San Angelo, TX or Sioux City, IA safer?

San Angelo is safer with a higher safety score by 11 points. San Angelo, TX has a safety score of 71/100 while Sioux City, IA has 60/100, based on FBI Uniform Crime Report data.

What is the violent crime rate in San Angelo, TX vs Sioux City, IA?

San Angelo, TX has a violent crime rate of 218.2 per 100,000 residents, while Sioux City, IA has 555.4 per 100,000. Lower rates indicate safer communities. The national average is approximately 380 per 100,000.

What is the property crime rate in San Angelo, TX vs Sioux City, IA?

San Angelo, TX has a property crime rate of 2486.0 per 100,000, compared to 3324.0 per 100,000 in Sioux City, IA. Property crimes include burglary, theft, and motor vehicle theft.

How are CrimeSafe safety scores calculated?

Safety scores range from 0-100, combining violent crime rates, property crime rates, and population data from the FBI UCR. Higher scores mean safer cities. Grades: A (80+), B (65-79), C (50-64), D (40-49), F (below 40).

Should I move to San Angelo, TX or Sioux City, IA?

Based on crime data alone, San Angelo is safer. However, safety is just one factor — also consider cost of living, job market, schools, and quality of life. Visit our city pages for more details on each.